The perimeter of the sector is ( 12 \text{ cm} ) and the area of the sector is ( 9 \text{ cm}^2 ). Show that ( r^2 – 6r + 9 = 0 \).
The perimeter of the sector is ( 12 \text{ cm} ) and the area of the sector is ( 9 \text{ cm}^2 ). Show that ( r^2 – 6r + 9 = 0 \).