What is the enthalpy change for the reaction in $kJ \cdot mol^{-1}$?
$C_{2}H_{2}(g) + 2H_{2}(g) \rightarrow C_{2}H_{6}(g)$
Given standard enthalpies of combustion ($\Delta H_{c}^{\theta}$ / $kJ \cdot mol^{-1}$):
$C_{2}H_{2}(g)$: $-1301$
$H_{2}(g)$: $-286$
$C_{2}H_{6}(g)$: $-1561$